# What is the volume of the solid produced by revolving #f(x)=1/x-1/x^2, x in [2,6] #around the x-axis?

##### 1 Answer

Dec 18, 2016

#### Explanation:

The portion of the graph of f(x) in the interval [2,6] looks like in the figure below:

If this portion is revolved around x-axis, the volume of the solid so generated can be worked out as follows:

Consider an element of the area enclosed by the x-axis and the curve, at a distance x from the origin and length y= f(x). If this is rotated about x-axis a circular disc of area

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