# What is the volume of the solid produced by revolving #f(x)=sqrt(1+x^2)# around the x-axis?

##### 2 Answers

Nov 17, 2016

# V = pi[x+1/3x^3]_a^b #

#### Explanation:

The volume of revolution about

# V = int_a^b piy^2dx #

so with

# V = int_a^b pi(sqrt(1+x^2))^2dx #

# :. V = piint_a^b 1+x^2 dx #

# :. V = pi[x+1/3x^3]_a^b #

As you have not specified the

Nov 17, 2016

See answer below: