What is the wavelength, in meters, of an alpha particle with a kinetic energy of 8.010^-13 J. [mass of an alpha particle = 4.00150 amu; 1 amu = 1.6710^–27 kg]?

Question

8828 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-21T14:31:28

#6.4 × 10^-15\ "m"#

de-Broglie wavelength is given by

#λ = h/p#

Relation between #p# and #"K"# is

#p = sqrt("2Km")#

So, the wavelength now becomes

#λ = h/sqrt("2mK")#

Where

#λ = (6.626 × 10^-34\ "J s")/sqrt(2 × 4.00150 cancel"amu" × 1.67 × 10^-27\ "kg"/cancel"amu" × 8.0 × 10^-13\ "J")#

#color(white)(λ) = 6.4 × 10^-15\ "m"#

#color(white)(λ) = 6.4\ "fm"#

What is the wavelength, in meters, of an alpha particle with a kinetic energy of 8.0*10^-13 J. [mass of an alpha particle = 4.00150 amu; 1 amu = 1.67*10^–27 kg]?