# What is the wavelength, in meters, of an alpha particle with a kinetic energy of 8.0*10^-13 J. [mass of an alpha particle = 4.00150 amu; 1 amu = 1.67*10^–27 kg]?

##### 1 Answer

Jun 21, 2018

#### Explanation:

de-Broglie wavelength is given by

#λ = h/p#

Relation between

#p = sqrt("2Km")#

So, the wavelength now becomes

#λ = h/sqrt("2mK")#

Where

#λ =# Wavelength of particle#h =# Planck’s constant#p =# Momentum of particle#"m ="# Mass of particle#"K ="# Kinetic energy of particle