What is the weight in grams of 3.36 * 10^23 molecules of copper sulfate CuSO_4?

1 Answer
Jun 7, 2016

~=89.1 \ g

Explanation:

Do the following conversions:

"Molecules "-> \ "mol. "-> "grams"

3.36xx10^23\ "molecules "CuSO_4xx ( 1 \ mol. CuSO_4)/ ( 6.02xx10^23 \ "molecules "CuSO_4)

3.36xx10^23\ cancel("molecules "CuSO_4)xx( 1 \ mol. CuSO_4)/ ( 6.02xx10^23 \ cancel("molecules "CuSO_4 ))

= 0.558 \ mol.\ CuSO_4

The molar mass of CuSO_4 = 159.57 \ g/(mol)

0.558 \ mol. \ CuSO_4xx(159.57 \ g \ CuSO_4)/(1\ mol. \ CuSO_4)

0.558 \ cancel (mol. \ CuSO_4)xx(159.57 \ g \ CuSO_4)/(1\ cancel(mol. \ CuSO_4))

~=89.1 \ g

Note that CuSO_4 is copper (II) sulfate.