What is the weight (on earth) of a 13.5-gram object?

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Answer 1 · 2018-03-17T12:30:35

#0.1323# Newtons #(N)#

#1#(#N#)#=#1#(kg**m)/(s^2)#

The acceleration due to gravity, g, is #9.8##(m)#/#(s^2)#
Mass, m=#(13.5gm)#**#(1kg)#/#(1000gm)# =#0.0135##(kg)#

The Weight force is #W=mg##(N)#
Therefore
#W=#(0.0135#kg#)**(9.8#m/s^2#) =#0.1323##(N)#

Answer 2 · 2018-03-17T13:47:29

#~~0.132 \ "N"#

Well, weight is expressed through the equation:

#W=mg#

where #m# is the mass of the object in kilograms, #g# is the gravitational acceleration constant, which is around #9.81 \ "m/s"^2#.

So, we first need to convert #13.5 \ "g"# into #"kg"#. Recall that, #1 \ "kg"=1000 \ "g"#, so here, we got:

#13.5 \ "g"=0.0135 \ "kg"#

And so, weight of the object will be

#W=0.0135 \ "kg"*9.81 \ "m/s"^2#

#=0.132435 \ "kg m/s"^2#

But we know that #1 \ "N"= 1 \ "kg m/s"^2#, and so we got:

#=0.132435 \ "N"#

#~~0.132 \ "N"#