Question

What is the width of a rectangle if its perimeter is 216 centimeters and its width is 24 centimeters less than its length?

Answer 1

The width is 42 centimeters long and the length is 66 centimeter long

Explanation:

First of all, let's translate the problem into mathematical notation.
We have a rectangle whose width `w` and length `l` are unknowns.

The first condition is that the perimeter `p` is `216` cm long. The perimeter can be computed as twice the width plus twice the length, so:
`p=2w+2l Rightarrow 2w+2l=216`

The second condition is that `w` is `24` cm less than `l`, so:
`w=l-24`

Now we can substitute `w` from the second condition into the first and solve the equation:
`2w+2l=216`
`2(l-24)+2l=216`
`2l-48+2l=216`
`4l=264`
`l=66`

Let's plug `l=66` in the second condition and get
`w=l-24`
`w=66-24=42`