What is the #x#-coordinate of the vertex of the parabola #y=x^2+6x#?

1 Answer
Mar 15, 2018

The x-coordinate value of the vertex is given by #color(blue)(-3#

Explanation:

Given:

#color(red)(y=x^2+6x#

We must find the x-coordinate value of the Vertex of the parabola.

For a parabola of the form #color(blue)(ax^2+bx+c#,

the x-coordinate value of the vertex is given by #color(blue)(-b/(2a)#

In #color(red)(y=x^2+6x#, we can see that #color(green)(a=1, and b = 6#.

When we use the formula, #color(blue)(-b/(2a)#, we get

#color(blue)(x=-(6)/(2*1))=-6/2 = -3#

Hence, the x-coordinate value of the vertex is given by #color(blue)(-3#

You can also examine the image of the graph below:

enter image source here

Hope it helps.