What is the #x#-intercept of the graph of the equation #1/2x - 3y=8#?

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Answer 1 · 2016-07-01T16:03:56

#x = 16#

Every point on the #x#-axis has its y-value equal to 0.

To find the x-intercept, make #y=0#

#1/2x-3(0)=8#

#1/2x = 8 rArr x = 16#

Every point on the #y#-axis has its x-value equal to 0.

To find the y-intercept, make #x=0#

#1/2 (0) - 3y = 8#

#-3y = 8 rArr y = -8/3#