What is the #x#-intercept of the line represented by the equation #5x-3y=-2#?

1 Answer
Dwight
Dec 20, 2016

x = #-2/5#

Explanation:

To find an #x#-intercept, you set #y# = 0 in the equation and solve for #x#. This works because the #x#-intercept is the point where the function crosses the #x#-axis of course, and the #y#-coordinate of the #x#-axis is #y# = 0

So, if #y# = 0

5#x# = -2

x = #-2/5#

Related questions
Impact of this question
746 views around the world
You can reuse this answer
Creative Commons License