Question

What is the z-score of X, if n = 135, `mu= 74`, SD =3, and X =73?

Answer 1

`Z= (73-74)/(3/sqrt(135)) = -sqrt(135)/3`

Explanation:

The standard normal distribution simply converts the group of data in our frequency distribution such that the mean is 0 and the standard deviation is 1.

We can use: `z = (x-mu)/sigma` assuming we have `sigma`
but here we have instead SD = s;

`z = (x- mu)/(s/sqrt(n))`; where n is sample size...