What is #(x^2-36)/(x^2-2x-24)*(x+4)/(x)#?

1 Answer
Jul 25, 2016

While this is a multiplication of fractions, the numerators and denominators are not in factor form. Start off by factorising.

#((x+6)(x-6) xx (x+4))/((x-6)(x+4) xx x)#

=#((x+6)cancel((x-6)) xx cancel(x+4))/(cancel((x-6))cancel((x+4)) xx x)#

=#((x+6))/x#