What is #(((x^2yz^4)^3(xy^3z^2)^4)/(xy^3x^2))^2#?

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Answer 1 · 2016-12-22T01:08:50

#x^18y^24z^36#

We have:

#(((x^2yz^4)^3(xy^3z^2)^4)/(xy^3x^2))^2#

We'll work through the inner brackets first:

#((x^6y^3z^12x^4y^12z^8)/(xy^3x^2))^2#

Now let's simplify the numerator, then combine in the denominator, then finally square the result:

#((x^10y^15z^20)/(xy^3x^2))^2#

#(x^9y^12z^18)^2#

#x^18y^24z^36#