What is x if $4 = \frac{2}{3} x + 9 - \frac{1}{3} x$ $4=2/3x+9-1/3x$ ?

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Answer 1 · 2015-10-25T16:05:34

$x = - 15$ $x=-15$

Original Equation $4 = \frac{2}{3} x + 9 - \frac{1}{3} x$ $4=2/3x+9-1/3x$

Multiply everything by $3$ $3$ to remove the denominator

$(4 \cdot 3) = (\frac{2}{3} \cdot 3 \cdot x) + (9 \cdot 3) - (\frac{1}{3} \cdot 3 \cdot x)$ $(4*3) =(2/3*3*x)+(9*3)-(1/3*3*x)$

Rewrite the equation

$12 = 2 x + 27 - 1 x$ $12=2x+27-1x$

Collect like terms

$12 = 1 x + 27$ $12=1x+27$

Isolate x

$- 15 = 1 x$ $-15=1x$

$x = - 15$ $x=-15$

What is x if 4=2/3x+9-1/3x4=23x+9−13x4=2/3x+9-1/3x?