What is x if #(x+2)+(x-1)= 0#?

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Answer 1 · 2018-05-06T17:35:26

#x = -1/2#

As you have a '+' in front of the second parenthesis, you can remove them, to have the following:

# x +2 + x -1 = 0#

Which gives you:

#2x +1 = 0#

You minus both side by 1:

#2x = -1#

And divide both side by 2, and then you get

#x = -1/2#

If this was a multiplication tho,

(x+2)(x-1) = 0, then you would have two possibilities of x, Either the first parenthesis = 0, or the second:

(x+2)= 0 or (x-1) = 0

Which gives you either

x = -2 or x =1