What is #x# in the equation #-4(x-3)^2 = 16#?

1 Answer
KillerBunny
Nov 10, 2015

The equation has no solutions.

Explanation:

You don't need to do many calculations: dividing both sides by negative four, you get

#(x-3)^2 = -4#

Since a square is always positive, or at least zero, this equation is impossible, because we're looking for a value such that a square is equal to someting negative.

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