What is #(y+x)-:2+x# for #x=1# and #y=1#?

1 Answer
Alan P.
Sep 21, 2016

#color(green)(2)#

Explanation:

If #color(blue)(x=1)# and #color(red)(y=1)#
then

#(color(red)(y)+color(blue)(x))div2+color(blue)(x)#

#color(white)("XXX")=(color(red)(1)+color(blue)(1))div2+color(blue)(1)#

#color(white)("XXX")=(2)div2+color(blue)(1)#

#color(white)("XXX")=1+color(blue)(1)#

#color(white)("XXX")=2#

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