# What mass of carbon dioxide is made when 22 g of propane is burned in oxygen?

Oct 13, 2016

66 grams of Carbon Dioxide.

#### Explanation:

The common currency of chemistry is moles. So it is necessary to change the mass of propane to moles. Then write a balance equation so the moles of propane to moles of Carbon Dioxide. Finally moles of Carbon Dioxide must be changed to grams.

${C}_{3} {H}_{8} + 5 {O}_{2} = = 3 C {O}_{2} + 4 {H}_{2} O$

This is the balance equation for the burning of propane in Oxygen.

From the equation it can be seen that 1 mole of propane makes 3 moles of Carbon Dioxide a ratio of 1:3

Convert 22 grams of propane to moles by dividing by the molar mass of propane.

3 x 12 = 36 grams
1 x 8 = + 8 grams
total = 44 grams/ mole.

$\frac{22}{44}$ = .5 moles of propane.

Using the ratio of 1:3 .5 = 3( .5) = 1.5 moles of Carbon Dioxide.

Now multiply 1.5 moles of Carbon Dioxide by the molar mass of Carbon Dioxide

1 x 12 = 12 grams
2 x 16 = +32 grams
total = 44 grams /mole.

1.5 moles x 44 grams/mole = 66 grams.