What mass of #"NaBr"# is needed to prepare #"50.00 mL"# of a #6.5%# (m/v) solution in distilled water?
So all you need to know in order to figure out a solution's mass by volume percent concentration is the number of grams of solute present for every
In your case, you know that you're dealing with a
So you can say that in order to get the equivalent of
#50.00 color(red)(cancel(color(black)("mL solution"))) * "6.5 g NaBr"/(100.0color(red)(cancel(color(black)("mL solution")))) = color(darkgreen)(ul(color(black)("3.3 g NaBr")))#
The answer is rounded to two sig figs, the number of sig figs you have for the mass by volume percent concentration.
To make this solution, you would dissolve