What mass of NaHCO3 would be needed to neutralize a spill consisting of 25.2mL of 6.01 M hydrochloric acid solution?

1 Answer
anor277
May 21, 2018

Approx. #13*g#....

Explanation:

We address the stoichiometric equation....

#Na^+HCO_3^(-) +HCl(aq)rarrNaCl(aq) +H_2O(l) + CO_2(g)uarr#

And thus there is 1:1 molar equivalence between hydrochloric acid and sodium bicarbonate...

#n_"HCl"=25.2*mLxx10^-3*L*mL^-1xx6.01*mol*L^-1=0.152*mol#

#"mass"_"sodium bicarbonate"=0.152*molxx84.01*g*mol^-1=??*g#

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