What mass of oxygen is needed to react with 4.5g of ethane #C_2H_8#?

1 Answer
Oct 9, 2016

Answer:

We need approx. #17*g# of dioxygen.

Explanation:

A balanced chemical equation is required:

#H_3C-CH_3 + 7/2O_2(g) rarr 2CO_2(g) +3H_2O(g)#

And thus each equiv ethane requires #7/2# equiv of dioxygen.

#"Moles of ethane"# #=# #(4.5*g)/(30.07*g*mol^-1)# #=# #0.15*mol#

And thus we need:

#7/2xx0.15*molxx32.00*g*mol^-1" dioxygen gas"# #=# #??g#