What mass of silver (Ag) contains the same number of atoms as 50.6 g of boron (B)?

1 Answer
Sep 18, 2017

Answer:

Approx. #500*g#.............

Explanation:

#"Moles of boron"=(50.6*g)/(10.81*g*mol^-1)=4.68*mol#

Now remember that the mole is simply a number, i.e. #6.022xx10^23*mol^-1#... And to get the same number of silver atoms, all I have to do is multiply this molar quantity by the molar mass of silver, #107.9*g*mol^-1#.....

And so, #107.9*g*mol^-1xx4.68*mol-=??#