Question

What mass of sodium hydroxide is needed to prepare 2.0L of 0.25mol L-1 of NaOH solution?

Answer 1

`"Option B"`

Explanation:

We approach the problem dimensionally, and we find that we need a molar quantity of...

`2.0*Lxx0.25*mol*L^-1=0.5*mol`. Since we know that molar mass of sodium hydroxide is `40.0*g*mol^-1`, we need a mass of `20*g` of stuff.