What mass of vitamin D ( molar mass 384.86g/mol) is needed to prepare 1250.0 ML of 2.29 M vitamin D solution?

1 Answer
May 10, 2018

#"1102 g"#

Explanation:

Molarity is given by

#"Molarity" = "Moles of solute"/"Volume of solution (in litres)"#

Taking following into consideration

  • #"Moles" = "Mass"/"Molar mass"#

  • #"Volume in litres" = "Volume in millilitres"/"1000 mL/L"#

We can rewrite the Molarity formula as

#"Molarity" = "Mass of solute"/"Molar mass of solute" × 1000/"Volume of solution (in mL)"#

#"Mass of Vitamin D" = "2.29 M × 384.86 g/mol × 1250.0 mL"/"1000 mL/L" ≈ "1102 g"#