What mass of chlorine occupies 33.6 L at STP?
1 Answer
Explanation:
For starters, you should know that STP conditions are defined as a pressure of
Under these conditions,
#"1 mole ideal gas " stackrel(color(white)(acolor(red)("STP conditions")aaa))(color(blue)(->)) " 22.72 L"#
So, the first thing to do here is to figure out the number of moles of chlorine gas,
To do that, use the molar volume of a gas at STP
#33.6 color(red)(cancel(color(black)("L"))) * "1 mole Cl"_2/(22.72color(red)(cancel(color(black)("L")))) = "1.479 moles Cl"_2#
To convert this to grams, sue the molar mass of chlorine gas
#1.479 color(red)(cancel(color(black)("moles Cl"_2))) * "70.906 g"/(1color(red)(cancel(color(black)("mole Cl"_2)))) = color(darkgreen)(ul(color(black)("105 g")))#
The answer is rounded to three sig figs, the number of sig figs you have for the volume of the gas.