What NaCl concentration results when 254 mL of a 0.800 M NaCl solution is mixed with 627 mL of a 0.480 M NaCl solution?

1 Answer
anor277
Apr 17, 2018

Approx. #0.6*mol*L^-1#....

Explanation:

#"Concentration"="Moles of solute"/"Volume of solution"#. And we ASSUME (reasonably) that the volumes of sodium chloride solution are ADDITIVE, and thus we take the quotient....

#(0.254*Lxx0.800*mol*L^-1+0.627*Lxx0.480*mol*L^-1)/(0.254*L+0.627*L)#

...which gives an answer in #mol*L^-1# as required...

And so #[NaCl]=0.572*mol*L^-1#...

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