Question

What pressure is exerted by 0.344 mol of `N_2` in a 9.73 L steel container at 105.4°C?

Answer 1

This is a clear application of the Ideal Gas equation..........I get approx. `1*atm`.............

Explanation:

`P=(nRT)/V=(0.344*cancel(mol)xx0.0821*(cancelL*atm)/(cancelK*cancel(mol))xx378.5*cancelK)/(9.73*cancelL)`

`~=1*atm`