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What quadrant will the product of (2+ 3i) and (-3 -4i) be located in?

1 Answer

Jul 20, 2017

The product lies in $4$ $4$ th quadrant at $(6, - 17)$ $(6,-17)$

Explanation:

$(2 + 3 i) \cdot (- 3 - 4 i) = - 6 - 8 i - 9 i - 12 i^{2}$ $(2+3i)*(-3-4i) = -6 -8i -9i -12 i^2$

$= - 6 - 17 i + 12 [i^{2} = - 1] = 6 - 17 i$ $= -6 -17i+12 [i^2=-1]= 6 -17i$ i.e

$6$ $6$ unit in positive x -axis and $17$ $17$ unit in negative y-axis.

So the product lies in $4$ $4$ th quadrant at $(6, - 17)$ $(6,-17)$ [Ans]

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