What's #b^((3c+1))=5a-d# written in logarithmic form?
1 Answer
Jan 11, 2018
See the answer below...
Explanation:
#b^((3c+1))=5a-d#
#=>log{b^((3c+1))}=log(5a-d)" "# [take log both side]
#=>(3c+1) cdot logb=log(5a-d)# This is the logarithmic form.
Hope it helps...
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