Question

What's the derivative of `arctan(x^2+1)`?

Answer 1

`d/dx`arctan(`x^2 +1`) = `(1/(1+(x^2+1)^2))*2x`

Explanation:

Consider the derivative of arctan(u)

`d/dx arctan(u) = (1/(1+u^2)) * d/dx (u)`

In your question: u = `(x^2+1)`