Question

What's the mass of HCl that will be produced from 655 kg of NaCl if the yield of the process is 84.5%?

2NaCl + H2SO4 -> Na2SO4 + 2HCl

I am confused. I have tried to work it out, but I think I am wrong... Any help?

Answer 1

Given equation for the reaction is,

`2NaCl + H_2 SO_4 = Na_2 SO_4 +2HCl`

So,we can see from the reaction that `2` moles of `HCl` is obtained from `2` moles of `NaCl`

Now,mass of `1` mole of `NaCl` is `(23+35.5)=58.5g` and that of `HCl` is `(1+35.5)=36.5 g`

So,we will get, `2*36.5 g` of `HCl` from `2*58.5g` of `NaCl` due to the reaction,

Then we should get, `(2*36.5)/(2*58.5) (655*1000)=408675.214g` of `HCl` from `655Kg` of `NaCl`

But,given, `%` yield is `84.5,`,so in reality amount of `HCl` produced will be `(408675.214)(84.5/100)=345330.556g=345.32Kg`