What’s the volume of 277 grams of ammonia gas , NH3 ?

1 Answer
anor277
Apr 19, 2018

Well, we must assume standard conditions of #1*atm# and #298*K# to attempt this question....I get approx. #400*L#...

Explanation:

#V=(nRT)/P=#

#((277*g)/(17.03*g*mol^-1)*0.0821*L*atm*K^-1*mol^-1xx298*K)/(1*atm)#

#=??*L#

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