What the derivative of #1/x#?

Question

507 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-12-09T16:05:27

#-1/x^2#

#(1/x)'=((1)'-1(x)')/x^2=-1/x^2#

Answer 2 · 2017-12-09T16:05:44

#-1/x^2#

Since #1/x=x^-1#,

#d/dx(1/x)=d/dx(x^-1)#

We can differentiate this with the powers rule

#d/dx(1/x)=-x^-2#
#=-1/x^2#