What transformation can you apply to #y=sqrtx# to obtain the graph #y=-2sqrt(3(x-4))+9#?

1 Answer
Dec 17, 2016

See explanation below

Explanation:

We go from #y=sqrtx#

to #y=-2sqrt(3(x-4))+9#

We compare this to

#y=asqrt(b(x+c))+d#

#a=-2# flips the graph upside down

#b=3# horizontal stretch

#c=-4# horizontal shift to the right

#d=9# vertical shift up

graph{(y-sqrtx)(y+2sqrt(3(x-4))-9)=0 [-14.59, 36.74, -5.92, 19.75]}