What transformation can you apply to $y=sqrtx$ to obtain the graph $y=-2sqrt(3(x-4))+9$ ?

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Answer 1 · 2016-12-17T16:27:15

See explanation below

We go from $y=sqrtx$

to $y=-2sqrt(3(x-4))+9$

We compare this to

$y=asqrt(b(x+c))+d$

$a=-2$ flips the graph upside down

$b=3$ horizontal stretch

$c=-4$ horizontal shift to the right

$d=9$ vertical shift up

graph{(y-sqrtx)(y+2sqrt(3(x-4))-9)=0 [-14.59, 36.74, -5.92, 19.75]}

What transformation can you apply to y=sqrtxy=sqrtx to obtain the graph y=-2sqrt(3(x-4))+9y=-2sqrt(3(x-4))+9?