# What type of reaction is: ammonium nitrate -> dinitrogen monoxide + water?

Jul 14, 2017

You have got $N {H}_{4} \cdot N {O}_{3}$, i.e. $N \left(- I I I\right)$ and $N \left(+ V\right)$, and the nitrogens end up with a common oxidation state of $\stackrel{+ I}{N}$ (individually $N + \left(I I\right)$ and $N \left(0\right)$.
$N {H}_{4} N {O}_{3} + \Delta \rightarrow {N}_{2} O + 2 {H}_{2} O$
For nitrous oxide, ${N}_{2} O$, we have a Lewis structure of $N \equiv \stackrel{+}{N} - \stackrel{-}{O} \leftrightarrow \stackrel{-}{N} = \stackrel{+}{N} = O$