What value of #k# will make #x^2-1/4x + k# a perfect square trinomial?

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Answer 1 · 2018-01-29T05:01:27

#1/64#

#x^2-1/4x+k#

#x^2-1/4x+(1/(4*2))^2#
you must add a term that's half of the #x# term squared, to get a perfect square trinomial

#x^2-1/4x+(1/8)^2#

#x^2-1/4x+1/64#

#(x+1/8)^2#

so comparing, we get the value of k as #1/64# !

-Sahar