# What value of x satisfies the equation 7/3(x+9/28) = 20?

Nov 7, 2016

$x = \frac{33}{4} = 8 \frac{1}{4}$

#### Explanation:

The starting equation is:

## $\frac{7}{3} \left(x + \frac{9}{28}\right) = 20$

The first step is to multiply both sides by $3$:

$7 \left(x + \frac{9}{28}\right) = 60$

Now we divide both sides by $7$

$x + \frac{9}{28} = \frac{60}{7}$

$x = \frac{60}{7} - \frac{9}{28}$

$x = \frac{240}{28} - \frac{9}{28}$

$x = \frac{231}{28} = \frac{33}{4} = 8 \frac{1}{4}$