# What volume (in mL) of ".220 M" ethanol solution contains 2.90 xx 10^-3 "mol" ethanol?

Jun 17, 2017

#### Explanation:

$\text{Volume of EtOH" = 2.90 × 10^"-3" color(red)(cancel(color(black)("mol EtOH"))) × "1 L EtOH"/(0.220 color(red)(cancel(color(black)("mol EtOH")))) = "0.0132 L EtOH" = "13.2 mL EtOH}$

Jun 17, 2017

$\text{13.2 mL}$

#### Explanation:

The idea here is that the molarity of the solution can be converted to the number of moles of solute present in

$\text{1 L} = {10}^{3}$ $\text{mL}$

of solution. In your case, a $\text{0.220-M}$ solution of ethanol will contain $0.220$ moles of ethanol for every ${10}^{3}$ $\text{mL}$ of solution.

This implies that $2.90 \cdot {10}^{- 3}$ moles of ethanol will be present in

2.90 * color(blue)(cancel(color(black)(10^(-3))))color(red)(cancel(color(black)("moles ethanol"))) * overbrace((color(blue)(cancel(color(black)(10^3)))color(white)(.) "mL solution")/(0.220color(red)(cancel(color(black)("moles ethanol")))))^(color(blue)("= 0.220 M"))

$= \textcolor{\mathrm{da} r k g r e e n}{\underline{\textcolor{b l a c k}{\text{13.2 mL solution}}}}$

The answer is rounded to three sig figs.