What volume is occupied by 0.35 mol of helium gas at SATP?

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Maxwell Share
Jul 18, 2017

Answer:

#"7.84 L"#

Explanation:

I will assume that you mean #"STP (Standard Temperature and Pressure)"#.

Since we know that #"1 mole"# of an ideal gas occupies #"22.4 L"# at #"STP"#, then can establish the following relationships:

#color(white)(------)color(orange)[("22.4 L")/("1 mole") or ("1 mole")/("22.4 L")#

Knowing that, we can solve for the volume occupied by the helium gas,

#(0.35 cancel"mole")/(1) * ("22.4 L")/(1 cancel"mole") = color(blue)"7.84 L"#

as #color(blue)"7.84 L"#

#--------------------#

The answer makes sense because if #"1 mole"# occupies #"22.4 L"#, then #"0.35 moles"# (roughly a third of the moles) will occupy a third of #"22.4 L" ("if we round down 22.4 L to 21 L")#

#color(white)(--------)21/3 ~~"7 L"#

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