# What volume of 1.25 M CaF_2 solution is needed to provide 4.00 mol CaF_2?

May 29, 2016

3.2 L of 1.25M CaF2

#### Explanation:

For this problem, you will need to know the formula for molarity.

$M o l a r i t y = \frac{m o l}{v o l u m e \left(L\right)}$

or

$M = \frac{n}{V}$

Given:

M = 1.25
n = 4.00 mol

$1.25 = \frac{4.00 m o l}{V}$
$V$ = 3.2 L