# What volume of 1.5M NaOH is needed to provide 0.75 mol of NaOH?

We require an half a litre volume of the given solution........and gets a $0.50 \cdot L$ volume...........
$\frac{0.75 \cdot \cancel{m o l}}{1.50 \cdot \cancel{m o l} \cdot {L}^{-} 1} = \frac{0.50}{{L}^{-} 1} = 0.50 \cdot \frac{1}{\frac{1}{L}} = 0.50 \cdot L$