# What volume of a 2.5 M stock solution of acetic acid is required to prepare 100.0 milliliters of a .50 M acetic acid solution?

Aug 22, 2016

$20. \text{milliliters}$ of acetic acid is required

#### Explanation:

Whenever you are dealing with a dilution, (going from a higher concentration to a lower concentration), you can use the equation below:

Let's determine our known and unknown variables:

color(blue)("Knowns:"

color(orange)("Unknowns:"

• Initial Volume

Next, we rearrange the equation to solve for ${V}_{1}$ by dividing by ${M}_{1}$ on both sides of the equation:

${V}_{1} = \frac{{M}_{2} \times {V}_{2}}{M} _ 1$

Plug in the known values and solve for your unknown:
${V}_{1} = \left(0.50 \cancel{\text{M"xx100.0mL)/(2.5cancel"M}}\right)$

Therefore,

${V}_{1} = 20. m L$