What volume will 4.91 x 10^22 atoms of Ne occupy at STP? a) 1.10 L b) 2.00 L c) 2.24 L d) 3.11 L e) 1.83 L

1 Answer
Junaid Mirza
Apr 7, 2018

#"e) 1.83 L"#

Explanation:

#"1 mol" = 6.022 × 10^23\ "atoms"#

#4.91 × 10^22\ "atoms" = 4.91 × 10^22 cancel"atoms" × "1 mol"/(6.022 × 10^23\ cancel"atoms") = "0.0816 mol"#

According to #"STP"# (before #1982#): 1 mol of any gas at #"1 atm"# and #"273.15 K"# occupies #"22.4 L"#

#"0.0816 mol"# of gas at #"STP"# will occupy a volume of

#0.0816 cancel"mol" × "22.4 L"/(1 cancel"mol") = "1.83 L"#

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