# What will be the volume of 3.65 g of oxygen gas be at STP?

Jun 20, 2018

Well...$V = \frac{n R T}{P}$..I get approx. $3 \cdot L$

#### Explanation:

And so $P = \frac{100 \cdot k P a}{101.3 \cdot k P a \cdot a t {m}^{-} 1}$...I use atmospheres instead of $k P a$ because I think the units are more accessible...

$V = \frac{\frac{3.65 \cdot g}{32.00 \cdot g \cdot m o {l}^{-} 1} \times 0.0821 \cdot \frac{L \cdot a t m}{K \cdot m o l} \times 273.15 \cdot K}{\frac{100 \cdot k P a}{101.3 \cdot k P a \cdot a t {m}^{-} 1}}$

=??*L

Note that you must simply KNOW that oxygen is diatomic...in fact all the elemental gases with any chemistry are diatomic...