# What will be the equivalent weight of #KClO_3# in the following equation ?

##
#3KClO_3 + 3H_2SO_4 → 3KHSO_4 + HClO_4 + 2ClO_2 + H_2O #

##### 2 Answers

#### Answer:

The equivalent weight is183.82 g.

#### Explanation:

The usual formula for calculating the equivalent weight (

where

For a **disproportionation reaction**, as you have above, we must modify the formula to

#"EW" = "MW"/N = "MW"/n_1 + "MW"/n_2#

where

We can factor out

#1/N = 1/n_1 + 1/n_2#

We can solve this equation to get

#color(blue)(bar(ul(|color(white)(a/a)N = (n_1n_2)/(n_1 + n_2)color(white)(a/a)|)))" "#

**For the oxidation half-reaction**

**For the reduction half-reaction**

**For the overall reaction**

∴

#### Answer:

Here's another way to solve the problem.

#### Explanation:

The **equivalent weight** is the molecular weight (**per mole of reactant** (

#color(blue)(bar(ul(|color(white)(a/a)"Equivalent weight" = "MM"/ncolor(white)(a/a)|)))" "#

We need the moles of electrons, so let's balance the equation by the ion-electron method.

Unbalanced equation:

Reduction:

Oxidation:

Overall:

We see that 2 mol of electrons are transferred in the reaction.

Since 3 mol of

∴

The equivalent weight of ** in this reaction** is 183.82 g.