What would be a polynomial equation with the root 2+i? Please also name another root of this equation. Thank You :)

1 Answer
Oct 30, 2017

An example with real coefficients would be:

#x^2-4x+5 = 0#

which also has root #2-i#

Explanation:

If any coefficients are allowed then a polynomial equation of minimum degree with root #2+i# is:

#x - (2+i) = 0#

This linear polynomial equation has no other roots.

Typically what is wanted is not a polynomial with complex coefficients, but one with real coefficients.

If so, then any non-real complex roots will occur in complex conjugate pairs (essentially because #i# and #-i# are indistinguishable from the perspective of the real numbers).

So if #2+i# is one root, then another would be #2-i#.

A polynomial of minimum degree with these zeros would be:

#(x-(2+i))(x-(2-i)) = ((x-2)-i)((x-2)+i)#

#color(white)((x-(2+i))(x-(2-i))) = (x-2)^2-i^2#

#color(white)((x-(2+i))(x-(2-i))) = x^2-4x+4+1#

#color(white)((x-(2+i))(x-(2-i))) = x^2-4x+5#

So we can write a suitable equation as:

#x^2-4x+5=0#