What would be a polynomial equation with the root 2+i? Please also name another root of this equation. Thank You :)
1 Answer
An example with real coefficients would be:
#x^2-4x+5 = 0#
which also has root
Explanation:
If any coefficients are allowed then a polynomial equation of minimum degree with root
#x - (2+i) = 0#
This linear polynomial equation has no other roots.
Typically what is wanted is not a polynomial with complex coefficients, but one with real coefficients.
If so, then any non-real complex roots will occur in complex conjugate pairs (essentially because
So if
A polynomial of minimum degree with these zeros would be:
#(x-(2+i))(x-(2-i)) = ((x-2)-i)((x-2)+i)#
#color(white)((x-(2+i))(x-(2-i))) = (x-2)^2-i^2#
#color(white)((x-(2+i))(x-(2-i))) = x^2-4x+4+1#
#color(white)((x-(2+i))(x-(2-i))) = x^2-4x+5#
So we can write a suitable equation as:
#x^2-4x+5=0#