What would be steps in proving that [(tan2x)/(secx + 1)] + 1 = sec x ?

Question

[(sec2x - 1)/(secx + 1)] + 1

[(secx - 1)(secx + 1)/(secx + 1)] + 1

(secx - 1) + 1

None of these

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Answer 1 · 2018-04-17T02:02:33

As proved.

#(tan^2 x / (sec x + 1)) + 1#

#=> ((sec^2 x - 1) / (sec x + 1)) + 1#

#=>(((sec x +1 ) * (sec x - 1)) / (sec x + 1)) + 1#

#=>((cancel(secx + 1) * (sec x - 1)) / (cancel(sec x + 1)) + 1)#

#=> sec x + cancel1 - cancel1 color(indigo)(= sec x = R H S#