What would be the concentration of a solution made by diluting 45.0 mL of 4.2 M KOH to 250 mL?

1 Answer
Apr 8, 2017

Answer:

As always, #"concentration"="Moles of solute"/"Volume of solution"..........#

Explanation:

And here (i) we calculate the #"moles of solute"# in the initial volume:

#=45xx10^-3Lxx4.2*mol*L^-1=0.189*mol# with respect to #KOH(aq)#.

And then (ii) we divide this value by the NEW volume of solution:

#"Concentration"=(0.189*mol)/(0.250*L)~=0.8*mol*L^-1# with respect to #KOH#.

The volume has increased approx. fivefold, and hence the concentration decreases approx. fivefold........