What would be the mass of three moles of ammonia?

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Answer 1 · 2017-12-24T18:50:30

This is ammonia,

#NH_3# where #AW approx (17g)/(mol)#

Hence,

#3mol * (17g)/(mol) approx 51g#

is the mass given your data.

Answer 2 · 2017-12-25T00:11:25

See the step process below..

Recall..

#"no of moles" = ("mass")/("molar mass")#

#n = m/(Mm)#

Where;

#n = 3mols#

#Mm = NH_3 = 14 + (1)3 = 14 + 3 = 17gmol^-1#

#m = ?#

Making #m# the subject..

#m = n xx Mm#

#m = 3mols xx 17gmol^-1#

#m = 51g#