What would be the volume of 6.00 g of helium gas at STP?
To answer this question, we'll need to use the Ideal Gas Law:
The question already gives us the values for
We also already know the gas constant. In our case, we'll use the value of
We can find the value for
Now, we can just plug all of these values in and solve for
Assuming that helium behaves as an ideal gas, we know that a mole of ideal gas occupies 22.4 litres at STP.
The atomic weight of helium is 4 g/mol, so 6 g is 1.5 moles.
The volume occupied at STP, therefore, is 22.4 x 1.5 = 33.6 litres.