What would the second and third terms of an arithmetic sequence be if the first term is 6 and the fourth is 33?

1 Answer
May 16, 2018

The second term = 15, and the third term = 24

Explanation:

An arithmetic sequence can be written on the form
sn=an+b
We know that s1=6 and s4=33
Therefore: s4s1=(4a+b)-(a+b)=336=27
3a=27
a=9
As 6=9+b,
b=3
Therefore sn=9n3
We, therefore, get:
s1=193=6
s2=293=15
s3=393=24
s4=493=33